Answer:
40% Aqueous
Alcohol
Weight
(gr) = ρ (alcohol) x Volume Alcohol x
percent of Alcohol
= 0,789 gr/ml x 5(3,7 L) 1000 x 40%
= 0,789 gr/ml x (18,5x103) ml x
40%
= 5.838,6 gr = 5,8386 kg
Good Bourbon
Weight
(gr) = ρ (alcohol) x Volume Alcohol x
percent of Alcohol
= 0,789 gr/ml x 5(3,7 L) 1000 x 80%
= 0,789 gr/ml x (18,5x103) ml x 80%
= 11.677,2 gr = 11,6772 kg
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